*Question by steve paisley*: Can someone help me with this physics equation?

“Boy and girl start out 60m apart. Boy walks toward girl at 2m/s while girl runs toward boy at 3m/s. Where and when do they meet?”

I have tried numerous things… my paper is filthy with equations and data… but every single one of them leads me only halfway, I can’t seem to get a straight answer…

**Best answer:**

*Answer by poetinmotion*

did you try it as an algebra equation? I suck at math, but try using variables. i.e. girl (2m/s)(X)=60m and (3m)(X)=60m for the boy and subract? I could be Totally off…

**Add your own answer in the comments!**

**Effective Time Management**

Time Management Tips, Techniques And Skills

Effective Time Management

You only use one equation here. That distance = rate x time or d = (r)*(t)

Now, when they both meet, their time is the same. Obviously, the girl would probably have traveled farther. So if the girl traveled y meters then boy must traveled 60-y meters.

If you got the equation right, you should get 12 seconds. I leave the where to you.

let t = time (in seconds) the boy and girl meets

2t = distance boy walked to meet the girl

60 – 3t = distance girl walked to meet the boy

and when they meet they are at the same location so the two equations are equal therefore:

2t = 60-3t

2t + 3t = 60

5t = 60

t = 12

boy meets girl 12 seconds later at 2*12 = 24 meters

or girl meets boy at 60 – (3*12) = 24